What product will be formed from the Hofmann | vedclass

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(A) Hofmann exhaustive methylation involves the formation of a quaternary ammonium hydroxide followed by thermal decomposition (Hofmann elimination).

Vedclass · Accepted Answer

$CH_3-CH=CH_2$

Vedclass · Answer

(A) Hofmann exhaustive methylation involves the formation of a quaternary ammonium hydroxide followed by thermal decomposition (Hofmann elimination). The elimination follows Hofmann's rule,which states that the least substituted alkene is the major product. The nitrogen atom is attached to an isobutyl group $(CH_3-CH(CH_3)-CH_2-)$ and a propyl group $(-CH_2-CH_2-CH_3)$. Elimination from the propyl group yields propene $(CH_3-CH=CH_2)$,which is a monosubstituted alkene. Elimination from the isobutyl group yields isobutylene $(CH_3-C(CH_3)=CH_2)$,which is a disubstituted alkene. According to Hofmann's rule,the less substituted alkene,propene,is the major product.

What product will be formed from the Hofmann exhaustive methylation of the following compound?
$CH_3-CH(CH_3)-CH_2-NH-CH_2-CH_2-CH_3 \xrightarrow[(i) CH_3I (excess), (ii) Ag_2O, (iii) \Delta]{} \text{Product}$

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What product will be formed from the Hofmann exhaustive methylation of the following compound? $CH_3-CH(CH_3)-CH_2-NH-CH_2-CH_2-CH_3 \xrightarrow[(i) CH_3I (excess), (ii) Ag_2O, (iii) \Delta]{} \text{Product}$